Hi,

I am developing an addin for visual studio 2005-using C#.
I have developed a tool window where i need to display the output of a function in the datagrid of the toolwindow.
The output is the List content which needs to be displayed.

First i have developed a class:
class line_num_keywords
{
public int line_number;
public string captured_word;
public line_num_keywords(int l_no,string c_key)

{
this.line_number = l_no;
this.captured_word = c_key;
}

Where this class stores the line number and words in a list:

List<line_num_keywords> data_holder = new List<line_num_keywords>();
.
.
.
.
data_holder.Add(new line_num_keywords(e.Line,input_array[keyword_number]));

This List created- has to bedisplayed in the datagrid.
how can i achieve this? please can any one help me with the code?
The list has to be displayed when the toolWindow is loaded.

Thanks,
Nayana

Hi NavanaKalkur,

It is not very complicated to binding the List<> with DataGridView.
Just set the DataSource property is OK.
List<line_num_keywords> data_holder = new List<line_num_keywords>();
data_holder.Add(new line_num_keywords(e.Line,input_array[keyword_number]));
...
dataGridView1.DataSource = data_holder;

Everything is fine, isn't it??

If there's any problem, please feel free to let me know.

Best regards,
Steven Yu

Hi NavanaKalkur,

It is not very complicated to binding the List<> with DataGridView.
Just set the DataSource property is OK.
List<line_num_keywords> data_holder = new List<line_num_keywords>();
data_holder.Add(new line_num_keywords(e.Line,input_array[keyword_number]));
...
dataGridView1.DataSource = data_holder;

Everything is fine, isn't it??

If there's any problem, please feel free to let me know.

Best regards,
Steven Yu