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hi,
i have 40 forms in my project.i stored the form name and formid in a table.What i want is while loading my application i want to list this all forms name in a tree view model under one parent.And while clicking i want to load that particular form.Any body can send the code for that
thanks elby - Moved byeryangMSFTWednesday, September 23, 2009 2:25 AM (From:.NET Base Class Library)
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| | Elby Paul Tuesday, September 22, 2009 5:31 AM | By the way you can bind your tree view using this code with data base:
private TreeView tView = new TreeView();
public void PopulateTree()
{
DataTable dt = new DataTable();
Hashtable ht = new Hashtable();
SqlConnection conn = new SqlConnection("data source=tstsvr;initial catalog=TreeTest;integrated security=SSPI;");
new SqlDataAdapter("SELECT * FROM Nodes ORDER BY NodeLevel Asc", conn).Fill(dt);
foreach (DataRow r in dt.Rows)
{
int nodeLvl = int.Parse(r["NodeLevel"].ToString());
string nodeParent = r["Parent"].ToString();
string nodeName = r["Name"].ToString();
TreeNode tNode = new TreeNode(nodeName);
ht.Add(nodeLvl.ToString() + nodeName, tNode);
if (tView.Nodes.Count == 0)
tView.Nodes.Add(tNode);
else
{
nodeLvl --;
((TreeNode) ht[nodeLvl.ToString() + nodeParent]).Nodes.Add(tNode);
}
}
ht.Clear();
}
Thanks,
Varun Kumar- Proposed As Answer byvarun007 Tuesday, September 22, 2009 6:00 AM
- Marked As Answer byKira QianMSFT, ModeratorTuesday, September 29, 2009 5:29 AM
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| | varun007 Tuesday, September 22, 2009 5:59 AM | why you are storing forms in data base? use Tree view control directly and give your form's name there. on click u can load forms from there.
Varun Kumar | | varun007 Tuesday, September 22, 2009 5:42 AM | but the forms are not predefined | | Elby Paul Tuesday, September 22, 2009 5:48 AM | Please explain the structure ofyour application first.
Kind regards,
Varun Kumar | | varun007 Tuesday, September 22, 2009 5:54 AM | By the way you can bind your tree view using this code with data base:
private TreeView tView = new TreeView();
public void PopulateTree()
{
DataTable dt = new DataTable();
Hashtable ht = new Hashtable();
SqlConnection conn = new SqlConnection("data source=tstsvr;initial catalog=TreeTest;integrated security=SSPI;");
new SqlDataAdapter("SELECT * FROM Nodes ORDER BY NodeLevel Asc", conn).Fill(dt);
foreach (DataRow r in dt.Rows)
{
int nodeLvl = int.Parse(r["NodeLevel"].ToString());
string nodeParent = r["Parent"].ToString();
string nodeName = r["Name"].ToString();
TreeNode tNode = new TreeNode(nodeName);
ht.Add(nodeLvl.ToString() + nodeName, tNode);
if (tView.Nodes.Count == 0)
tView.Nodes.Add(tNode);
else
{
nodeLvl --;
((TreeNode) ht[nodeLvl.ToString() + nodeParent]).Nodes.Add(tNode);
}
}
ht.Clear();
}
Thanks,
Varun Kumar- Proposed As Answer byvarun007 Tuesday, September 22, 2009 6:00 AM
- Marked As Answer byKira QianMSFT, ModeratorTuesday, September 29, 2009 5:29 AM
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| | varun007 Tuesday, September 22, 2009 5:59 AM | Hi, may be it will help you.
private void treeView1_AfterSelect(object sender, TreeViewEventArgs e)
{
switch(e.Node.Text)
{
case "Form2":
Form2 frm2 = new Form2();
frm2.Show();
break;
default:
break;
}
}
Best Regards,
C.Gnanadurai
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Please mark the post as answer if it is helpfull to you | | Gnanadurai Tuesday, September 22, 2009 6:24 AM |
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