index > Windows Forms General > Invoke Activated Child Method

Invoke Activated Child Method

Hi guys,

I need to know how to activate the Active child method.

For example, I create 2 newchild A and B (both the same form), I want to get Form A and print.

How do I do that.

Thanks.

Noobie and Newbie Tuesday, May 22, 2007 10:59 AM

Here's a simple example:

public partial class Form1 : Form {
public Form1() {
InitializeComponent();
}
private void toolStripButton1_Click(object sender, EventArgs e) {
Form2 f2 = new Form2();
f2.MdiParent = this;
f2.Show();
}
private void toolStripButton2_Click(object sender, EventArgs e) {
Form2 f2 = this.ActiveMdiChild as Form2;
if (f2 != null) f2.DoSomething();
}
}

nobugz Tuesday, May 22, 2007 3:22 PM

Could you explain your problem clearly

E.Veera Raghavendra Tuesday, May 22, 2007 11:06 AM

Here's a simple example:

public partial class Form1 : Form {
public Form1() {
InitializeComponent();
}
private void toolStripButton1_Click(object sender, EventArgs e) {
Form2 f2 = new Form2();
f2.MdiParent = this;
f2.Show();
}
private void toolStripButton2_Click(object sender, EventArgs e) {
Form2 f2 = this.ActiveMdiChild as Form2;
if (f2 != null) f2.DoSomething();
}
}

nobugz Tuesday, May 22, 2007 3:22 PM

private void Print_Click(object sender, EventArgs e)

{

Product product = this.ActivateMdiChild as Product;

if (product != null)

{

product.Print();

}

}

got error

Cannot convert type 'method group' to 'Ippcm Product' via a built-in conversion.

Product is my application Form(child).

Thanks nobugz

Noobie and Newbie Thursday, May 24, 2007 9:09 AM

Active, not Activate.

nobugz Thursday, May 24, 2007 10:13 AM

Thanks, nobugz. Stupid of me to see things wrong.

Noobie and Newbie Friday, May 25, 2007 2:03 AM

You can use google to search for other answers

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