Hi

Write a new Constructor and define a member to form 2.

private Form1 frm1=null;
public Form2(Form1 frm)
{
InitializeComponent();
frm1=frm;
}

At Form1 whilecreating an instance ofform2 use this constructor.

Form2 frm2=new Form2(this);
frm2.Show();

At Form2 Write this code to the click event of button

((Label)frm.Controls.Find("myLabel",true)[0]).Visible=false; /or true

the problem is I cannot change the visible property of a label resides on the form1 through a button tha resides on the form2. i write the code, no compile error, ijust doesnt work. nothing happens??
why? thats my problem

In form 2:

public string MyTextBoxText
{
get { return myTextBox.Text; }
set { myTextbox.Text = value; }
}

public bool MyTextBoxVisible
{
get { return myTextBox.Visible; }
set { myTextBox.Visible = value; }
}

In form 1 (must have a reference to form 2):

form2.TextBoxText = "Hello World";
form2.TextBoxVisible = true;

[Edit] Wasn't really paying attention, you want labels and you want it the other way around. So just replace myTextBox with the label name, and switch form 1/form 2

[Edit2] I'm assuming you're opening form 2 from form 1. So to get a reference to form 1 you'll need to either pass it in the constructor:

Form2 form2 = new Form2(this); // 'this' is form1

Or create an event in form 2 whenever you want it to change (more complicated but the correct way to do it, form2 doesn't even have to know form1 exists)

AKGMA why not use FindControl method of controls collection?

ex:

this

.Controls.Find("myControl",true)

the label that i want to change its visible property resides on form1 but after opening form2 from form1 and doing some calculation i want to change the visible and text property of label that resides on form1 through a button that resides on form2.
it doesnt wirk with your solution.
regards

Hi

Write a new Constructor and define a member to form 2.

private Form1 frm1=null;
public Form2(Form1 frm)
{
InitializeComponent();
frm1=frm;
}

At Form1 whilecreating an instance ofform2 use this constructor.

Form2 frm2=new Form2(this);
frm2.Show();

At Form2 Write this code to the click event of button

((Label)frm.Controls.Find("myLabel",true)[0]).Visible=false; /or true