Hi all!

I have two buttons on my form. myButton01 and myButton02.

When myButton01 is clicked, it calls the method private void hitBtn_Click(object sender, EventArgs e). This works fine.

On the second button I placed the Click property to the same method as above.

In this method for myButton02, I wanted to add additionalcode to the methodrather then making a duplicate codes for myButton02.

So, I guess my question is, how can I tell if myButton02 is clicked in this method?

Any help would be appreciated.

Dave

You don't. (*)

(*) Yes, what you ask can be done. But it shouldn't be.

If I understood you correctly, you can use the following:

private void hitBtn_Click(object sender, EventArgs e)

{

Button temp_btn = ( Button)sender;

// code for both buttons

if(temp_btn.Name ==Btn2.Name)

{

//additional code for Button2

}

}

The reason I wanted to encourage doing it at compile-time instead of run-time, is because run-time methods lead to bad designs:

The "correct" way of doing that:

}

You don't. (*)

(*) Yes, what you ask can be done. But it shouldn't be.

Thanks James,

I started writing my code to your suggested path and that seems to work.

Should I always avoidthe otherlogic?

and curiously, how would the other way be known?

If I understood you correctly, you can use the following:

private void hitBtn_Click(object sender, EventArgs e)

{

Button temp_btn = ( Button)sender;

// code for both buttons

if(temp_btn.Name ==Btn2.Name)

{

//additional code for Button2

}

}

Because it has you doing things at run-time which can & should be done at compile-time.

Hi dan!

Yes, this is what I was looking for. I tried both ways of programming and they both worked.

Many of my questions are very, very beginner level in this forum. So, anything that will make me understand better is greatly appreciated.

Thanks and another question will arrive soon enough.

Dave

The reason I wanted to encourage doing it at compile-time instead of run-time, is because run-time methods lead to bad designs:

The "correct" way of doing that:

}